(02-03-2025, 01:35 PM)Albert Wrote: A negative value (or -1) in the settings window usually means that the setting is disabled.
Hi Albert, thanks for the reply. However, I encountered some strange things in generating the NC Code. With the same path and post-processor (GCode NCP), but different settings in the program tab, the generated NC Codes have some differences. In line N00006, one angle A is positive, and one angle A is negative.
This code is generated from the default setting: Minimum step size (mm) 0.005, Maximum step size (mm) -1.00, Maximum step size (deg) -1.00
Code:
; Program P20kg_circle_0
N00001 F15000 ; Set default speed
; Program generated by RoboDK v5.8.0 for autonox articc6-1803-20kg (AT-00014)_md on 06/02/2025 09:30:30
; Using nominal kinematics.
F60000.000
; Using reference frame: X=378.000 Y=1062.000 Z=251.500 A=0.000 B=0.000 C=0.000
; Tool frame set to: Werkzeugwechsler
; X=0.000 Y=0.000 Z=0.000 A=0.000 B=0.000 C=0.000
N00003 M72 T=-1
; N00004 M108 T=... ; Set Drillbit typenumber (not implemented)
; Anzeigen Werkzeugwechsler
N00005 G00 Q1=53.774200 Q2=27.704000 Q3=82.894400 Q4=0.000000 Q5=69.401600 Q6=53.774200
N00006 G07 X=778.000 Y=1062.000 Z=251.500 A=180.000 B=-0.000 C=180.000
F3000.000
N00007 G07 X=777.272 Y=1037.886 Z=251.500 A=180.000 B=-0.000 C=180.000
N00008 G07 X=774.571 Y=1009.736 Z=251.500 A=180.000 B=-0.000 C=-180.000
N00009 G07 X=769.887 Y=981.846 Z=251.500 A=180.000 B=-0.000 C=180.000
N00010 G07 X=763.244 Y=954.358 Z=251.500 A=180.000 B=-0.000 C=180.000
N00011 G07 X=754.676 Y=927.407 Z=251.500 A=-180.000 B=-0.000 C=180.000
N00012 G07 X=744.225 Y=901.129 Z=251.500 A=180.000 B=-0.000 C=-180.000
N00013 G07 X=731.943 Y=875.656 Z=251.500 A=180.000 B=-0.000 C=180.000
N00014 G07 X=717.892 Y=851.113 Z=251.500 A=-180.000 B=-0.000 C=-180.000
N00015 G07 X=702.143 Y=827.625 Z=251.500 A=180.000 B=-0.000 C=180.000
N00016 G07 X=684.773 Y=805.308 Z=251.500 A=-180.000 B=-0.000 C=180.000
N00017 G07 X=665.869 Y=784.275 Z=251.500 A=180.000 B=-0.000 C=180.000
N00018 G07 X=645.527 Y=764.629 Z=251.500 A=-180.000 B=-0.000 C=180.000
N00019 G07 X=623.847 Y=746.470 Z=251.500 A=180.000 B=-0.000 C=180.000
N00020 G07 X=600.939 Y=729.888 Z=251.500 A=-180.000 B=-0.000 C=180.000
This code is generated from the default setting: Minimum step size (mm) 0.01, Maximum step size (mm) 0.05, Maximum step size (deg) 1.00
Code:
; Program P20kg_circle_0
N00001 F15000 ; Set default speed
; Program generated by RoboDK v5.8.0 for autonox articc6-1803-20kg (AT-00014)_md on 06/02/2025 09:42:18
; Using nominal kinematics.
F60000.000
; Using reference frame: X=378.000 Y=1062.000 Z=251.500 A=0.000 B=0.000 C=0.000
; Tool frame set to: Werkzeugwechsler
; X=0.000 Y=0.000 Z=0.000 A=0.000 B=0.000 C=0.000
N00003 M72 T=-1
; N00004 M108 T=... ; Set Drillbit typenumber (not implemented)
; Anzeigen Werkzeugwechsler
N00005 G00 Q1=53.774200 Q2=27.704000 Q3=82.894400 Q4=0.000000 Q5=69.401600 Q6=53.774200
N00006 G07 X=778.000 Y=1062.000 Z=351.500 A=-180.000 B=-0.000 C=180.000
; Splitting Linear movement in 2000 (instruction 7: MoveL 3)
N00007 G07 X=778.000 Y=1062.000 Z=351.450 A=-180.000 B=-0.000 C=180.000
N00008 G07 X=778.000 Y=1062.000 Z=351.400 A=-180.000 B=-0.000 C=180.000
N00009 G07 X=778.000 Y=1062.000 Z=351.350 A=-180.000 B=-0.000 C=180.000
N00010 G07 X=778.000 Y=1062.000 Z=351.300 A=-180.000 B=-0.000 C=180.000
N00011 G07 X=778.000 Y=1062.000 Z=351.250 A=-180.000 B=-0.000 C=-180.000
N00012 G07 X=778.000 Y=1062.000 Z=351.200 A=-180.000 B=-0.000 C=180.000
N00013 G07 X=778.000 Y=1062.000 Z=351.150 A=-180.000 B=-0.000 C=180.000
N00014 G07 X=778.000 Y=1062.000 Z=351.100 A=-180.000 B=-0.000 C=180.000
N00015 G07 X=778.000 Y=1062.000 Z=351.050 A=-180.000 B=-0.000 C=180.000
N00016 G07 X=778.000 Y=1062.000 Z=351.000 A=-180.000 B=-0.000 C=180.000
N00017 G07 X=778.000 Y=1062.000 Z=350.950 A=-180.000 B=-0.000 C=180.000
N00018 G07 X=778.000 Y=1062.000 Z=350.900 A=-180.000 B=-0.000 C=-180.000
N00019 G07 X=778.000 Y=1062.000 Z=350.850 A=-180.000 B=-0.000 C=-180.000
N00020 G07 X=778.000 Y=1062.000 Z=350.800 A=-180.000 B=-0.000 C=180.000
Do you know what could be the possible solution to it? Thanks again for the reply with deep gratitude.